Imagine an electric current leaving a battery. If the resistors are connected in such a way that part of the current can go through one resistor and the rest of the current can go through another resistor, then the circuit is a parallel circuit.
IT is the total current of the parallel circuit. You would measure this current anywhere before or after the three-way split leading to the three resistors. In between the junction and R1, you would measure I1. Between the junction and R2, you would measure I2 etc.
Since the total current, IT, splits up into three different groups of electrons, each traveling their route,
IT = I1 + I2 + I3 +….
In parallel circuits, all resistors, regardless of their resistances, experience the same voltage drop or potential difference because they all have the same entry and exit points (junctions).
VT = V1 = V2 = V3 =Vn
If we divide the current formula by the voltage relationship we obtain:
or RT = [R1-1 + R2-1 + R3-1 + …]-1
12W 12W 12W
a. What is the total resistance of the circuit?
RT = [R1-1 + R2-1 + R3-1]-1
RT = [12-1 + 12-1 +12-1]-1 = 4 W
b. What is the total current?
IT = V/RT = 12/4 = 3 A
c. What voltage (V1) would be measured across each individual resistor?
12 V (Voltage is constant in parallel.)
c. What current is drawn out by each resistor?
I1 = V/R1 = 12/12 = 1A. The rest also draw 1 A each, for a total of 3A.
Remember voltage is constant in parallel. So if we find V1, we will know V2.
V1 = I1R1 = 1(10) = 10 V.
V2 = V1 = 10 V.
R2= V/I2 = 10/0.5 = 20W.
(1) RT = [R1-1 + R2-1 ]-1 = [20-1 + 10-1 ]-1= 6.7 W.
(2) IT = I3 = I1 + I2 = 1 + 0.5 = 1.5 A.
RT = V/ IT =10/1.5 = 6.7 W.
In a parallel circuit, what effect does adding more resistors have on total current?
In a series circuit, adding more resistors increases total resistance and thus lowers current. But the opposite is true in a parallel circuit because adding more resistors in parallel creates more choices and lowers total resistance. If the same battery is connected to the resistors, current will increase. Not convinced? Try it:
[10-1 + 10-1]-1 = 5 W, but add a resistor in parallel and you get [10-1 + 10-1 + 10-1]-1 = only 3.3 W. With less resistance, you’re faced with a higher total current.
Another interesting thing about parallel circuits is that if one component is turned off, the other pathways are still viable, so that electrons can continue to flow through the circuit. This is the reason that most lights and sockets in a home are wired in parallel.