Stoichiometry Review Details to #5 solutions

I don’t have the original questions with me, but make sure the equation is balanced before the ratios are set.

5) a. 5 moles of Li₃PO₄(3 HF/1 Li₃PO₄) = 15 moles HF

b. 9.8 g/(98g/mole) = 0.10 moles H₃PO₄

0.10 moles H₃PO₄(3 LiF/1 H₃PO₄) = 0.30 moles LiF

c. 1 mole LiF (1 H₃PO₄/3 LiF) = 0.33 moles H₃PO₄

0.33 moles H₃PO₄(98g/mole) = 32.7 g

d. 200g HF/(20g/mole) = 10 moles HF

10 moles HF(3LiF/3HF) = 10 moles LiF

10 moles LiF (26 g/mole) = 260 g